Using a small set of rules, you can solve the number of particles in any isotope.
Rules:
|
Example 1: fill in the blanks.
isotope | atomic # |
p+ | n | e– | mass # |
charge |
beryllium-9 | 0 |
Solution 1:
•atomic number = 4 (beryllium is element 4 on the Periodic Table)
•# of protons = 4 (same as atomic number)
•mass number = 9 (from the isotope name)
•# of neutrons = 5 (subtract atomic number from mass number)
•# of electrons = 4 (electrons = protons in a neutral element)
isotope | atomic # |
p+ | n | e– | mass # |
charge |
beryllium-9 | 4 | 4 | 5 | 4 | 9 | 0 |
Example 2
isotope name |
atomic number |
protons | neutrons | electrons | mass number |
charge |
11 | 13 | 10 |
Solution:
•atomic number = 11 (same as # of protons)
•mass number = 24 (protons + neutrons)
•isotope name is “sodium-24” (element name and mass number)
•charge is +1 (protons – electrons)
isotope name |
atomic number |
protons | neutrons | electrons | mass number |
charge |
sodium-24 | 11 | 11 | 13 | 10 | 24 | +1 |
Example 3:
isotope name |
atomic number |
protons | neutrons | electrons | mass number |
charge |
23 | 49 | +3 |
Solution:
•element is vanadium (element 23 on Periodic Table)
•isotope name is “vanadium-49” (element name and mass number)
•# of protons = 23
•# of neutrons = 26 (mass number minus protons)
•# of electrons = 20 (charge = protons – electrons; +3 = 23 – x)
isotope name |
atomic number |
protons | neutrons | electrons | mass number |
charge |
vanadium-49 | 23 | 23 | 26 | 20 | 49 | +3 |
Extra comments about electrons and charge:
•if charge is negative, it will have more electrons than protons
•if charge is positive it will have less electrons than protons
•if charge is zero, it will have equal numbers of electrons and protons