Alkane molecules have only single bonds () between carbon atoms.
Alkene molecules have a double bond ().
Alkyne molecules have a triple bond ().
The following examples show the 4 carbon alkane, alkene, and alkyne.
Notice that the alkene only has one double bond and the alkyne only has one triple bond.
Name | Formula | Structure |
butane | C4H10 | |
butene | C4H8 | |
butyne | C4H6 |
All of the carbon atoms above have exactly 4 bonds.
A multiple-bonded C atom has less bonds available for H’s. That’s why butene (C4H8) has two less H atoms than butane (C4H10), and butyne(C4H6) has four less H’s than butane.
Generic Formula for Alkane / Alkene / Alkyne
Type | Generic Formula |
Example n = # of C’s |
Example 2n+2 = # of H’s |
Example Formula |
alkane | CnH2n+2 | n = 5 | 2n + 2 = 12 | C5H12 |
alkene | CnH2n | n = 5 | 2n = 10 | C5H10 |
alkyne | CnH2n-2 | n = 5 | 2n – 2 = 8 | C5H8 |
Example: If n=5, then 2n + 2 = 2(5) + 2 = 10 + 2 = 12
You can use these generic formulas to predict the formula for any alkane, alkene, or alkyne.
Example:
What is the molecular formula of a 32 carbon alkyne?
Solution:
•Generic formula is CnH2n-2
•# of C’s = n = 32
•# of H’s = 2n – 2 = 2(32) – 2 = 62
•Formula is C32H62
Naming Alkanes / Alkenes / Alkynes
Use a prefix (found here) to indicate the number of C’s.
Use the appropriate ending to show which type of molecule it is:
Type | Functional Group |
Name Ending |
alkane | (all single bonds) |
-ane |
alkene | (one double bond) |
-ene |
alkyne | (one triple bond) |
-yne |
Example 1: Name this molecule: |
Solution 1: It has 6 carbons, so the prefix is “hex-.” It has one double bond, so it’s an alkene and it ends with “-ene”. Its name is hexene.
Example 2: Draw pentyne.
Solution 2: It has 5 carbons since the prefix is “pent-.” It has one triple bond since the ending is “-yne.” There are multiple ways to draw this one depending on where you want to put the triple bond:
The first solution shows a triple bonded carbon on one end, while the second solution shows the triple bond somewhere in the middle. Both are correct structures for pentyne (they are isomers, and branched isomers also exist).